**Problem and solution**

If 10,000 voltage is applied across an x-ray tube, what will
be the ratio of the de Broglie
wavelengths of incident electron to that of the x-ray produced?

To solve this problem, we have to write the wavelength of the
electron in terms of the de Broglie concept. Here in the place of the momentum
we can write applied potential and the corresponding energy. Similarly to right
the wavelength of the x-ray, we can use plank’s quantum concept as shown below.

**Problems and solutions**

Here we are going to solve two problems. In the first problem and alpha particle and the proton are passed through same magnetic field which is perpendicular to the velocity vectors. If both the charger particles are having the same radius, what is the ratio of their de Broglie wavelengths?

We can solve this problem by first of all understanding that the force due to the magnetic field on the charged particle provides the necessary centripetal force so that they takes a circular path. From that it can be concluded that the momentum of the particle is directly proportional to charge of the particle as well as the radius of the particle. Anyway in this problem being the radius is same, we can say momentum means directly proportional to the charge of the particle itself.

As per this concept, wavelength is inversely proportional to momentum that means wavelength is inversely proportional to the charge of the given particles.

The second problem is also solved basing on the same concept as shown above.

**Problem and solution**

Photons of energy 4.25 electron volt and 4.7 electron volt
are allowed to incident on to metal surface S. If the maximum kinetic energies
between them are having a difference of 1.5 electron volts and the they are
wavelengths are in the ratio of 1:2, find the work functions of the two
different metals?

We can express de Broglie wavelength in terms of the kinetic
energy. Basing on this we can say that the ratio of the day Broglie wavelength
is inversely proportional to Squire root of ratio of their respective kinetic
energies. Taking this concept into consideration we can solve the problem as
shown below.

**Problem and solution**

de Broglie wavelength of the proton accelerated through a potential difference of 100 V is
given. If a alpha particle is accelerated through same potential difference,
what will be its wavelength?

According to de Broglie hypothesis, we know that the wavelength
of a particle is the ratio of Planck’s constant to the momentum of the
particle. We can express the momentum in terms of kinetic energy. Further we
can express the kinetic energy in terms of the applied potential. By
substituting the given data in that equation, we can solve the problem as shown
below.

**Problem and solution**

A light particle of a certain mass at rest explodes into two
particles having masses in the ratio of 2:3 . What is the corresponding ratio
of the de Broglie wavelengths?

As the particle is in the state of rest, its initial momentum
is equal to

**0**. The explosion is happened due to internal forces and hence law of conservation of momentum is very much valid here. According to this law the initial momentum of the system is equal to the final momentum when no external forces are acting on the system. As the momentum is as well as the Planck’s constant are same, the wavelengths are also going to be the same.**Problem and solution**

What will be the wavelength of electron having energy of
hundred electron volts?

We can solve this problem basing on dual nature of the
particle. Here the particles shall be having a wave nature and hence it shall
have certain wavelength which is equal to the ratio of Planck’s constant to
momentum of the particle. We can express the momentum in terms of kinetic
energy and the kinetic energy can be further expressed in terms of the applied
voltage.

By substituting the data in the given problem we can solve
the problem as shown below.

**Related Posts**

Dual Nature of Radiation and Matter complete lesson

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